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INVERSE TRIGNOMETRIC FUNCTIONS — Maths STD 12 Science — Question

Gujarat BoardEnglish MediumSTD 12 ScienceMathsINVERSE TRIGNOMETRIC FUNCTIONS1 Mark
Question
Find the value of $\tan^{-1}\Big(\tan\frac{9\pi}{8}\Big)$
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Answer

$\tan^{-1}\Big(\tan\frac{9\pi}{8}\Big)=\tan^{-1}\Big[\tan\Big(\pi+\frac{\pi}{8}\Big)\Big]$
$=\tan^{-1}\Big[\tan\Big(\frac{\pi}{8}\Big)\Big]$
$=\frac{\pi}{8}$

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