Question
Find the value of $\tan^{-1}\sqrt{3}-\cot^{-1}(-\sqrt{3}).$
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Answer
$\tan^{-1}\sqrt{3}-\cot^{-1}(-\sqrt{3}).$
$\frac{\pi}{3}-\frac{5\pi}{6}=\frac{2\pi-5\pi}{6}=\frac{-3\pi}{6}=\frac{-\pi}{2}$
$\frac{\pi}{3}-\frac{5\pi}{6}=\frac{2\pi-5\pi}{6}=\frac{-3\pi}{6}=\frac{-\pi}{2}$
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