MCQ
Find the value of the following determinant$:\ \begin{vmatrix}\displaystyle \frac{-4}{7} &\text{amp; } \displaystyle \frac{-6}{35}\\ 5 &\text{amp; } \displaystyle \frac{-2}{5}\end{vmatrix}$
  • A
    $\displaystyle \frac{15}{34}$
  • B
    $\displaystyle \frac{32}{45}$
  • C
    $\displaystyle \frac{25}{33}$​
  • $\displaystyle \frac{38}{35}$​

Answer

Correct option: D.
$\displaystyle \frac{38}{35}$​
The value of $\begin{vmatrix}\displaystyle \frac{-4}{7} \text{amp; } \displaystyle \frac{-6}{35}5\ \text{amp; } \displaystyle \frac{-2}{5}\end{vmatrix}$ is $\bigg(\frac{-4}{7}\times\frac{-2}{5}\bigg)-\bigg(\frac{-4}{7}\times5\bigg)$
$=\frac{8}{25}+\frac{30}{35}=\frac{38}{35}$

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