Question
Find the value of ? where $31k 2$ is divisible by $6.$

Answer

Given, $31k2$ is divisible by $6.$
Then, it is also divisible by $2$ and $3$ both.
Now, $31k2$ is divisible by $3,$
sum of its digits is a multiple of $3.$
i.e. $3 + 1 + k + 2 = 0, 3, 6, 9, 12, … $
$= k + 6 = 0, 3, 6, 9, 12 = k = 0 or 3, 6, 9$

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