Find the value of x, if: 14 x=(47)^2-(33)^2 - Vidyadip

Question

Find the value of $x$, if:
$14 x=(47)^2-(33)^2$

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Answer

Let us consider the following equation:
$14 x=(47)^2-(33)^2$
Using the identity $(a+b)(a-b)=a^2-b^2$
we get:
$14 x=(47)^2-(33)^2$
$14 x=(47+33)(47-33)$
$14 x=80 \times 14=1120$
$\Rightarrow 14 x=1120$
$\Rightarrow x=80 \text { (Dividing both sides by } 14 \text { ) }$

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