Find the value of x, if: 4 x=(52)^2-(48)^2 - Vidyadip

Question

Find the value of x, if:
$4 x=(52)^2-(48)^2$

✓

Answer

Let us consider the following equation:
$4 x=(52)^2-(48)^2$
Using the identity $(a+b)(a-b)=a^2-b^2$ we get:
$4 x=(52)^2-(48)^2$
$4 x=(52+48)(52-48)$
$4 x=100 \times 4=400$
$\Rightarrow 4 x=400$
$\Rightarrow x=100 \text { (Dividing both sides by } 4 \text { ) }$

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