MCQ
Find the value of x if $\begin{bmatrix}3&\text{3}\\2&\text{x}^2\end{bmatrix}=\begin{bmatrix}5&3\\3&2\end{bmatrix}.$
  • $\text{x}=1,-\frac{1}{3}$
  • B
    $\text{x}=-1,-\frac{1}{3}$
  • C
    $\text{x}=1,\frac{1}{3}$
  • D
    $\text{x}=-1,\frac{1}{3}$

Answer

Correct option: A.
$\text{x}=1,-\frac{1}{3}$
Given that $\begin{bmatrix}3&\text{3}\\2&\text{x}^2\end{bmatrix}=\begin{bmatrix}5&3\\3&2\end{bmatrix}$

$\Rightarrow3\text{x}^2-2\text{x}=5(2)-3(3)$

$⇒3\text{x}^2-2\text{x}=1$

solving for x, we get

$\text{x}=1,-\frac{1}{3}$

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