Question
Find the value of x, if:
$\begin{vmatrix}3&\text{x}\\\text{x}&1\end{vmatrix}=\begin{vmatrix}3&2\\4&1\end{vmatrix}$

Answer

Given, $\begin{vmatrix}3&\text{x}\\\text{x}&1\end{vmatrix}=\begin{vmatrix}3&2\\4&1\end{vmatrix}$$\Rightarrow3-\text{x}^2=3-8$
$\Rightarrow-\text{x}^2=-8$
$\Rightarrow\text{x}^2=8$
$\Rightarrow\text{x}=\pm2\sqrt{2}$

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