Question
Find the value $'x\ ',$ if:
✓
Answer
In right $\triangle ABC$,
$\sin 45^{\circ}=\frac{ BC }{ AC }$
$ \Rightarrow \frac{1}{\sqrt{2}}=\frac{15}{x}$
$ \Rightarrow x =15 \sqrt{2} \ cm .$
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