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Trigonometry – I — Maths STD 11 Science — Question

Maharashtra BoardEnglish MediumSTD 11 ScienceMathsTrigonometry – I1 Mark
Question
Find the values of : $\cos 1140^{\circ}$
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Answer

We know that cosine function is periodic with period $2 \pi$.
$ \cos 1140^{\circ}=\cos \left(3 \times 360^{\circ}+60^{\circ}\right)$
$=\cos 60^{\circ}=\frac{1}{2} $

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