Trigonometry – II — Maths STD 11 Science — Question
Maharashtra BoardEnglish MediumSTD 11 ScienceMathsTrigonometry – II2 Marks
Question
Find the values of : sin 150°
✓
Answer
$\begin{aligned} & \sin 15^{\circ}=\sin \left(45^{\circ}-30^{\circ}\right) \\ & =\sin 45^{\circ} \cos 30^{\circ}-\cos 45^{\circ} \sin 30^{\circ} \\ & \left(\frac{1}{\sqrt{2}}\right)\left(\frac{\sqrt{3}}{2}\right)-\left(\frac{1}{\sqrt{2}}\right)\left(\frac{1}{2}\right)=\frac{\sqrt{3}-1}{2 \sqrt{2}} \end{aligned}$ [Note: Answer given in the textbook is $\frac{\sqrt{3}+1}{2 \sqrt{2}}$ However, as per our calculation it is $\frac{\sqrt{3}-1}{2 \sqrt{2}}$
Need a full question paper?
Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.