Question
Find the values of : sin 690°

Answer

$
\begin{aligned}
& \sin 690^{\circ}=\sin \left(720^{\circ}-30^{\circ}\right) \\
& =\sin \left(2 \times 360^{\circ}-30^{\circ}\right) \\
& =-\sin 30^{\circ} \\
& =\frac{-1}{2}
\end{aligned}
$

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