Question
Find the values of : $\sin \frac{19 \pi^c}{3}$

Answer

We know that sine function is periodic with period $2 \pi$.
$\sin \frac{19 \pi}{3}=\sin \left(6 \pi+\frac{\pi}{3}\right)=\sin \frac{\pi}{3}=\frac{\sqrt{3}}{2}$

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