Question
Find the values of : tan (-690°)

Answer

\begin{aligned}
& \tan \left(-690^{\circ}\right)=-\tan 690^{\circ} \\
& =-\tan \left(720^{\circ}-30^{\circ}\right) \\
& =-\tan \left(2 \times 360^{\circ}-30^{\circ}\right) \\
& =-\left(-\tan 30^{\circ}\right) \\
& =\tan 30^{\circ} \\
& =\frac{1}{\sqrt{3}} \\
\end{aligned}

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