Question
Find the values of the following.
$(2 ^{-1}\times4^{-1})\div2^{-2}$

Answer

$(2 ^{-1}\times4^{-1})\div2^{-2}$
$=\Big(\frac{1}{2}\times\frac{1}{4}\Big )\div\frac{1}{2^2}$
$=\frac{1}{8}\div\frac{1}{4}=\frac{1}{8}\times\frac{4}{1}=\frac{1}{2}$

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