Question
Find the values of $x$ such that $f(x)$ is decreasing function:
$f(x)=2 x^3-15 x^2-84 x-7$

Answer

$
\begin{aligned}
& f(x)=2 x^3-15 x^2-84 x-7 \\
& \therefore f^{\prime}(x)=\frac{d}{d x}\left(2 x^3-15 x^2-84 x-7\right) \\
& =2 \times 3 x^2-15 \times 2 x-84 \times 1-0 \\
& =6 x^2-30 x-84 \\
& =6\left(x^2-5 x-14\right)
\end{aligned}
$
$f$ is decreasing, if $f^{\prime}(x)<0$
i.e. if $6\left(x^2-5 x-14\right)<0$
i.e. if $x^2-5 x-14<0$
i.e. if $x^2-5 x<14$
i.e. if $x-5 x+\frac{25}{4}<14+\frac{25}{4}$
i.e. if $\left(x-\frac{5}{2}\right)^2<\frac{81}{4}$
i.e. if $-\frac{9}{2}<x-\frac{5}{2}<\frac{9}{2}$
i.e. if $-\frac{9}{2}+\frac{5}{2}<x-\frac{5}{2}+\frac{5}{2}<\frac{9}{2}+\frac{5}{2}$
i.e. if $-2<x<7$
$\therefore f$ is decreasing, if $-2< x <7$.

Need a full question paper?

Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.

Start Generating Free