Question
Find the values of $x$ such that $f(x)$ is decreasing function:
$f(x)=x^4-2 x^3+1$

Answer

$
\begin{aligned}
& f(x)=x^4-2 x^3+1 \\
& \therefore f^{\prime}(x)=\frac{d}{d x}\left(x^4-2 x^3+1\right) \\
& =4 x^3-2 \times 3 x^2+0 \\
& =4 x^3-6 x^2
\end{aligned}
$
$f$ is decreasing, if $f^{\prime}(x)<0$
i.e. if $4 x^3-6 x^2<0$
i.e. if $x^2(4 x-6)<0$
i.e. if $4 x-6<0 \ldots \ldots\left[\because x^2>0\right]$
i.e. if $x<\frac{3}{2}$
i.e. $-\infty<x<\frac{3}{2}$
$\therefore f$ is decreasing, if $-\infty< x <\frac{3}{2}$.

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