Question
Find the variance and standard deviation of the random variable $X$ whose probability distribution is given below:
$x$0123
$P ( X =x)$$\frac{1}{8}$ $\frac{3}{8}$$\frac{3}{8}$$\frac{1}{8}$

Answer

$x_i$$p_i$$p_i x_i$$p_i x_i^2$
0$1 / 8$00
1$3 / 8$$3 / 8$$3 / 8$
2$3 / 8$$6 / 8$$12 / 8$
3$1 / 8$$3 / 8$$9 / 8$
 Total$12 / 8$$24 / 8$= 3

$E(X)=\mu=\sum p_i x_i=\frac{12}{8}=\frac{3}{2}$
$\operatorname{Var}(X)=\sum_{i=1}^n p_i x_i^2-\mu^2$
$\begin{aligned} & =3-\left(\frac{3}{2}\right)^2 \\ & =3-\frac{9}{4} \\ & =\frac{3}{4} \\ & \therefore \operatorname{Var}(X)=\sigma^2=\frac{3}{4}\end{aligned}$
Standard deivation of $(X)=\sigma_x=\sqrt{\frac{3}{4}}=\frac{\sqrt{3}}{2}$

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