Question
Find the vector equation of the plane passing through the point having position vector
$\hat{i}+\hat{j}+\hat{k}$ and perpendicular to the vector $4 \hat{i}+5 \hat{j}+6 \hat{k}$.
$\hat{i}+\hat{j}+\hat{k}$ and perpendicular to the vector $4 \hat{i}+5 \hat{j}+6 \hat{k}$.
vector $\bar{n}$ is $\bar{r} \cdot \bar{n}=\bar{a} \cdot \bar{n}$
Here, $\bar{a}=\hat{i}+\hat{j}+\hat{k}_1 \bar{n}=4 \hat{i}+5 \hat{j}+6 \hat{k}$
$\therefore \bar{a} \cdot \bar{n}=(\hat{i}+\hat{j}+\hat{k}) \cdot(4 \hat{i}+5 \hat{j}+6 \hat{k})$
= (1)(4) + (1)(5) + (1)(6) = 4 + 5 + 6 = 15
$\therefore$ the vector equation of the required plane is $\bar{r} \cdot(4 \hat{i}+5 \hat{j}+6 \hat{k})=15$.
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$\int_{-\pi / 4}^{\pi / 4} \frac{1}{1-\sin x} \cdot d x$