Question
Find the volume, curved surface area and total surface area of the cylinders whose dimensions are: Radius of the base $= 5.6\ m$ and height $= 1.25\ m.$

Answer

Radius of the base of the cylunder $(r), = 5.6m$ Height $(h) = 1.25m$
$a. \therefore$ Volume $=\pi\text{r}^2\text{h}$
$=\frac{22}{7}\times(5.6)^2\times1.25\text{cm}^3$
$=\frac{22}{7}\times5.6\times5.6\times1.25\text{m}^3$
$=123.2\text{m}^3$
$b.$ Lateral surface area $=2\pi\text{rh}$
$=2\times\frac{22}{7}\times5.6\times1.25\text{m}^2$
$=44\text{m}^2$
$c.$ Total surface area $=2\pi\text{r}(\text{h}+\text{r})$
$=2\times\frac{22}{7}\times5.6(1.25+5.6)$
$=44\times0.8(6.85)\text{m}^2$
$=241.12\text{m}^2$

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