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Volume and Surface Area of Solids — Maths STD 8 — Question

Maharashtra BoardEnglish MediumSTD 8MathsVolume and Surface Area of Solids4 Marks
Question
Find the volume of iron required to make an open box whose external dimensions are $36 cm \times 25 cm \times 16.5 cm$, the box being 1.5 cm thick throughout. If $1 cm^3$ of iron weighs 8.5 grams, find the weight of the empty box in kilograms.
✓

Answer

Outer length of open box $=36 cm$
Breadth $=25 cm$
And height $=16.5 cm$
Thickness of iron $=1.5 cm$.
$\therefore \text { Inner length }=36-2 \times 1.5=36-3$
$=33 cm,$
Breadth $=25-2 \times 1.5$
$=25-3$
$=22 cm$
And height $=16.5-1.5$
$=15 cm$
$\therefore$ Volume of iron used in it = Out volume - inner volume
$=36 \times 25 \times 16.5 cm^3-33 \times 22 \times 15 cm^3$
$=14850-10890$
$=3960 cm^3$
Weight of $1 cm^3=8.5$ gram
$\therefore \text { Total weight }=3960 \times 8.5 g$
$=33660 g$
$=33.660 kg$
$=33.66 kg$

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