Question
Find three repeater machines that will do the same work as a $(x64)$ machine. Draw them, or describe them using exponents.
✓
Answer
We know that, the possible factors of $64$ are $2, 4, 8:$
If $2^6= 64, 4^3= 64$ and $8^2= 64.$
Hence, three repeater machines that would work as a $(x64)$ will be $(x2^6 ), (x4^3)$ and $(x8^2)$. The diagram of $(x2^6), (x4^3)$ and $(x8^2)$ is given below.
Need a full question paper?
Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.
Explore more
Similar questions
The floor of a bullding consists of 3000 tiles, which are rhombus shaped and each of its diagonals are 45 cm and 30 cm In length. Find the total cost of polishing the floor, if the cost per $m ^2$ is ₹ 4 .
TIPS Firstly, find the area of floor by multiplying area of one tile with total number of tiles. Then, multiply area of floor by cost per $m^2$ to get total cost of polishing.
→TIPS Firstly, find the area of floor by multiplying area of one tile with total number of tiles. Then, multiply area of floor by cost per $m^2$ to get total cost of polishing.
If $x+y=12$ and $x y=14$, find the value of $\left(x^2+y^2\right)$.
→Factorise: $25a^2– 4b^2+ 28bc – 49c^2$
→Write the quotient and remainder when we divide: $\left(x^4-2 x^3+2 x^2+x+4\right)$ by $\left(x^2+x+1\right)$
→Find the following products:
$(3x^2- 4xy)(3x^2- 3xy)$
→$(3x^2- 4xy)(3x^2- 3xy)$
$A$ can do a piece of work in $10$ days while $B$ alone can do it in $15$ days. In how many days can both finish the same work?
→About $230$ billion litres of water flows through a river each day. How many litres of water flows through that river in a week? How many litres of water flows through the river in an year? Write your answer in standard notation.
→Find following products: $\Big(\frac{1}{3}\text{x}^2-9\Big)\Big(\frac{1}{3}\text{x}^2-9\Big)$
→Verify the following: $\Big(\frac{-8}{3}+\frac{-13}{12}\Big)\times\frac{5}{6}=\Big(\frac{-8}{3}\times\frac{5}{6}\Big)+\Big(\frac{-13}{12}\times\frac{5}{6}\Big)$
→If we fix time period and the rate of interest, simple interest changes proportionally with principal. Would there be a similar relationship for compound interest? Why?