Maharashtra BoardEnglish MediumSTD 10MathsQuadratic Equations3 Marks
Question
Find two consecutive natural numbers whose product is $20$.
✓
Answer
Let the two consecutive natural numbers be $'x'$ and $'x + 1'$
Given that product of the natural numbers is $20$
Hence, $x(x + 1) = 20$
$\Rightarrow x^2 + x = 20$
$\Rightarrow x^2 + x - 20 = 0$
$\Rightarrow x^2 + 5x - 4x - 20 = 0$
$\Rightarrow x(x + 5) - 4(x + 5) = 0$
$\Rightarrow x = -5$ or $x = 4$
Considering positive value of x as $\text{x}\in\text{N}$
For $r = 4, x + 1 = 4 + 1 = 5$
The two consecutive natural numbers are $4$ as $5$
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