Gujarat BoardEnglish MediumSTD 8MATHSRational Numbers3 Marks
Question
Find two rational numbers lying between $\frac{-1}{3}$ and $\frac{1}{2}$.
✓
Answer
Required number $=\frac{1}{2}\times\Big(\frac{-1}{3}+\frac{1}{2}\Big)$ $=\frac{1}{2}\times\Big(\frac{-2+3}{6}\Big)$ $=\frac{1}{2}\times\frac{1}{6}$ $=\frac{1}{12}$ $\frac{-1}{3}<\frac{1}{12}<\frac{1}{2}$ Required number between $\frac{-1}{3}$ and $\frac{1}{2}$: $=\frac{1}{2}\times\Big(\frac{-1}{3}+\frac{1}{12}\Big)$ $=\frac{1}{2}\times\Big(\frac{1-4}{12}\Big)$ $=\frac{1}{2}\times\Big(\frac{-3}{12}\Big)$ $=\frac{-3}{24}$ $=\frac{-3\div3}{24\div3}$ $=\frac{-1}{8}$ Thus, $\frac{1}{12}$ and $\frac{-1}{8}$ are two rational numbers between $\frac{-1}{3}$ and $\frac{1}{2}$.
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