Question
Find two solutions for equation: $3y + 4 = 0$

Answer

Writing the equation $3y + 4 = 0$ as $0.x + 3y + 4 = 0,$ you will find that $$$y = -\frac{4}{3}$ for any value of $x.$
Thus, two solutions can be given as $\left(0,-\frac{4}{3}\right) \text { and }\left(1,-\frac{4}{3}\right)$

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