Find where 0 (zero) is a term of the A.P. 40, 37, 34, 31, .....

Question

Find where $0$ (zero) is a term of the A.P. $40, 37, 34, 31, .....$

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Answer

A.P. $40, 37, 34, 31, .....$
Here,
$a = 40, d = -3$
Let $T_n = 0$
$T_n = a + (n - 1)d$
$\Rightarrow 0 = 40 + (n - 1)(-3)$
$\Rightarrow 0 = 40 - 3n + 3$
$\Rightarrow 3n = 43$
$\Rightarrow\ \text{n}=\frac{43}{3}$ which is in fraction
There is no term which is $0$.

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