MCQ
Find $x;$ if $\angle1=5\text{x}+15^\circ$ and $\angle2=28\text{x},$ angles form linear pair.
- A$40^\circ$
- B$140^\circ $
- ✓$5^\circ $
- D$20^\circ $
$\angle1+\angle2=180^\circ$ (Linear pair)
$\Rightarrow5\text{x}+15^\circ+28\text{x}=180^\circ$
$\Rightarrow33\text{x}=180^\circ-15=165^\circ$
$\Rightarrow\text{x}=\frac{165^\circ}{33}=5^\circ$
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