Question
Find $x$, if $g(x)=0$ where : $g(x)=6 x^2+x-2$

Answer

$\begin{aligned} & g(x)=6 x^2+x-2 \\ & g(x)=0 \\ & \therefore 6 x^2+x-2=0 \\ & \therefore 6 x^2+4 x-3 x-2=0 \\ & \therefore 2 x(3 x+2)-1(3 x+2)=0 \\ & \therefore(2 x-1)(3 x+2)=0 \\ & \therefore 2 x-1=0 \text { or } 3 x+2=0 \\ & \therefore x=\frac{1}{2} \text { or } x=\frac{-2}{3}\end{aligned}$

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