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Functions — Maths STD 11 Science — Question

Maharashtra BoardEnglish MediumSTD 11 ScienceMathsFunctions1 Mark
Question
Find $x$, if $g(x)=0$ where
$g(x)=x^3-2 x^2-5 x+6$
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Answer

$ g(x)=x^3-2 x^2-5 x+6$
$=(x-1)\left(x^2-x-6\right)$
$=(x-1)(x+2)(x-3)$
$g(x)=0$
$\therefore(x-1)(x+2)(x-3)=0$
$\therefore x-1=0 \text { or } x+2=0 \text { or } x-3=0$
$\therefore x=1,-2,3$

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