Question
Find $'x\ ',$ if :
✓
Answer
From the figure we have
$\tan 30^{\circ}=\frac{20}{x} $
$ \frac{1}{\sqrt{3}}=\frac{20}{x} $
$ x=20 \sqrt{3}$
$\tan 30^{\circ}=\frac{20}{x} $
$ \frac{1}{\sqrt{3}}=\frac{20}{x} $
$ x=20 \sqrt{3}$
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