Question
Find x in the following. $\frac{1}{6!}+\frac{1}{7!}=\frac{\text{x}}{8!}$

Answer

$\frac{1}{6!}+\frac{1}{7!}=\frac{\text{x}}{8!}$ $\Rightarrow\text{x}=\frac{8!}{6!}+\frac{8!}{7!}$ $\Rightarrow=\frac{8\times7\times6!}{6!}+\frac{8\times7!}{7!}$ $\Rightarrow\text{x}=8\times7+8$ $\Rightarrow\text{x}=64$

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