Question
Find x in the following.
$\frac{1}{6!}+\frac{1}{7!}=\frac{\text{x}}{8!}$
$\frac{1}{6!}+\frac{1}{7!}=\frac{\text{x}}{8!}$
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Find the 12th term from the end of the following arithmetic progressions,
3, 8, 13, ..., 253