Question
Find x in the following.
$\frac{1}{6!}+\frac{1}{7!}=\frac{\text{x}}{8!}$

Answer

$\frac{1}{6!}+\frac{1}{7!}=\frac{\text{x}}{8!}$
$\Rightarrow\text{x}=\frac{8!}{6!}+\frac{8!}{7!}$
$\Rightarrow=\frac{8\times7\times6!}{6!}+\frac{8\times7!}{7!}$
$\Rightarrow\text{x}=8\times7+8$
$\Rightarrow\text{x}=64$ 

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