Question
Find x in the following.
$\frac{\text{x}}{10!}=\frac{1}{8!}+\frac{1}{9!}$
$\frac{\text{x}}{10!}=\frac{1}{8!}+\frac{1}{9!}$
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12C10
$\frac{\text{x}+\text{e}^\text{x}}{1+\log\text{x}}$
$\frac{\text{e}^\text{x}+\sin\text{x}}{1+\log\text{x}}$