Question
Find $(x + y) ÷ (x − y)$, if $\text{x}=\frac{2}{5},\text{y}=\frac{1}{2}$
✓
Answer
$\text{x}=\frac{2}{5},\text{y}=\frac{1}{2}$
$\therefore\text{x}+\text{y}=\frac{2}{5}+\frac{1}{2}$
$=\frac{4+5}{10}=\frac{9}{10}$
$\text{x}-\text{y}=\frac{2}{5}-\frac{1}{2}$
$=\frac{4-5}{10}=\frac{-1}{10}$
$\therefore(\text{x}+\text{y})\div(\text{x}-\text{y})=\frac{9}{10}\div\frac{-1}{10}$
$=\frac{9}{10}\times\frac{10}{-1}$
$=\frac{9}{-1}=-9$
$\therefore\text{x}+\text{y}=\frac{2}{5}+\frac{1}{2}$
$=\frac{4+5}{10}=\frac{9}{10}$
$\text{x}-\text{y}=\frac{2}{5}-\frac{1}{2}$
$=\frac{4-5}{10}=\frac{-1}{10}$
$\therefore(\text{x}+\text{y})\div(\text{x}-\text{y})=\frac{9}{10}\div\frac{-1}{10}$
$=\frac{9}{10}\times\frac{10}{-1}$
$=\frac{9}{-1}=-9$
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