Question
Find x, y, z (whichever is required) from the figure given below:
✓
Answer
In $\triangle \text{ABC}$ and $\triangle \text{ADE}$ we have:
$\angle \text{ADE}=\angle \text{ABC}$ (Corresponding angles)
$\text{x}=40^\circ$
$\angle \text{AED}=\angle \text{ACB}$ (Corresponding angles)
$\text{y}=30^\circ$
We know that the sum of all the three angles of a triangle is equal to 180°
x + y + z = 180° $($Angles of $\triangle \text{ADE})$
Which means: 40° + 30° + z = 180°
z = 180° - 70°
z = 110°
Therefore, we can conclude that the three angles of the given triangle are 40°, 30° and 110°
$\angle \text{ADE}=\angle \text{ABC}$ (Corresponding angles)
$\text{x}=40^\circ$
$\angle \text{AED}=\angle \text{ACB}$ (Corresponding angles)
$\text{y}=30^\circ$
We know that the sum of all the three angles of a triangle is equal to 180°
x + y + z = 180° $($Angles of $\triangle \text{ADE})$
Which means: 40° + 30° + z = 180°
z = 180° - 70°
z = 110°
Therefore, we can conclude that the three angles of the given triangle are 40°, 30° and 110°
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