Question
Find$3 \div2 \frac{1}{3}$
✓
Answer
We have,
$3 \div 2 \frac{1}{3}=3 \div\left(\frac{2 \times 3+1}{3}\right)=3 \div\left(\frac{6+1}{3}\right)$
$
=3 \div \frac{7}{3}=3 \times \frac{3}{7}=\frac{3 \times 3}{7}=\frac{9}{7}
$
$3 \div 2 \frac{1}{3}=3 \div\left(\frac{2 \times 3+1}{3}\right)=3 \div\left(\frac{6+1}{3}\right)$
$
=3 \div \frac{7}{3}=3 \times \frac{3}{7}=\frac{3 \times 3}{7}=\frac{9}{7}
$
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