MCQ
First four terms of an A.P., are……………………whose first term is -2 and common difference is -2.
- A-2,0,2,4
- B-2,4,-8,16
- ✓2,-4,-6,-8
- D-2,-4,-8,-16
✓
Answer
Correct option: C.
2,-4,-6,-8
First, four terms of an A.P., are $=\mathbf{2},-\mathbf{4},-\mathbf{6},-\mathbf{8}$ whose first term is -2 and the common difference is -2 .Explanation:
Let the first four terms of an A.P are $a, a+d, a+2 d$ and $a+3 d$
Given that the first term is -2 and difference is also -2 , then the A.P would be:
-2,(-2-2),[-2+2(-2)],[-2+3(-2)] \
= -2,-4,-6,-8
Let the first four terms of an A.P are $a, a+d, a+2 d$ and $a+3 d$
Given that the first term is -2 and difference is also -2 , then the A.P would be:
-2,(-2-2),[-2+2(-2)],[-2+3(-2)] \
= -2,-4,-6,-8
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