Question
First $I.P.$ of $Mg$ is ...... than $Al$
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$\mathop {{H_3}C\mathop C\limits^ \ominus {H_2}}\limits_{(i)} \,,$$\mathop {{H_2}C = \mathop C\limits^ \ominus H}\limits_{(ii)} $ and $\mathop {H - C \equiv \mathop C\limits^ \ominus }\limits_{(iii)} $
is in the order of
