MCQ
First stable product of Calvin cycle has
  • A
    $2$ carbon atoms
  • $3$ carbon atoms
  • C
    $4$ carbon atoms
  • D
    $6$ carbon atoms

Answer

Correct option: B.
$3$ carbon atoms
b
(b) Ribulose -$1, 5$ biphosphate $(RuBP)$ acts as $CO_2$ acceptor and $6$ mols $RuBP$ react with $6$ mols of $CO_2$ and given rise to $3$ - phosphoglyceric acid, $3\ PGA$ is a first stable compound in $C_3$ cycle (a $3$ carbon atom).

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