Five capacitors together with their capacitances are shown in the adjoining figure. The potential difference between the points $A$ and $B$ is $60\, volt$. The equivalent capacitance between the point $A$ and $B$ and charge on capacitor $5 \mu F$ will be respectively:-
Medium
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$ \frac{1}{C_{e q}} =\frac{1}{8}+\frac{1}{24}+\frac{1}{12} $
$\Rightarrow C_{e q} =4\, \mu F$
$ V_{A}-V_{B} =60 \mathrm{\,V}$
$\mathrm{q}=\mathrm{C}_{\mathrm{eq}}\left(\mathrm{V}_{\mathrm{A}}-\mathrm{V}_{\mathrm{B}}\right)=240\, \mu \mathrm{C}$
Charge on $5 \mu \mathrm{F}$ Capacitor $=\frac{240}{24} \times 5=50\, \mu \mathrm{C}$
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