MCQ
Fluorine is highly reactive because:
- A$F-F$ bond energy is high.
- ✓$F-F$ bond energy is low.
- Cit is gaseous at room temperature.
- D$F$ has a smaller size.
✓
Answer
Correct option: B.
$F-F$ bond energy is low.
$F_2$ is highly reactive because of its low bond energy. Also, it has the highest electronegativity.
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