MCQ
For a biased die the probabilities for different faces to turn up are given below

$Face:$ $1$ $2$ $3$ $4$ $5$ $6$
$Probability:$ $0.1$ $0.32$ $0.21$ $0.15$ $0.05$ $0.17$

The die is tossed and you are told that either face $1$ or $2$ has turned up. Then the probability that it is face $1$, is

  • $\frac{5}{{21}}$
  • B
    $\frac{5}{{22}}$
  • C
    $\frac{4}{{21}}$
  • D
    None of these

Answer

Correct option: A.
$\frac{5}{{21}}$
a
(a) Required probability $ = \frac{{0.1}}{{0.1 + 0.32}} = \frac{{0.1}}{{0.42}} = \frac{5}{{21}}.$

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