MCQ
For a $d$ electron, the orbital angular momentum is
- ✓$\sqrt {6\hbar } $
- B$\sqrt {2\hbar } $
- C$\hbar $
- D$2\hbar $
For $d -$ orbital, $1=2$
Thus, the orbital angular momentum is $=\sqrt{6} \frac{ h }{2 \pi}$
$\sqrt {6\hbar } $
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$\mathrm{SO}_3, \mathrm{H}_2 \mathrm{SO}_3, \mathrm{SOCl}_2, \mathrm{SF}_4, \mathrm{BaSO}_4, \mathrm{H}_2 \mathrm{~S}_2 \mathrm{O}_7$
$C{O_2} + 2{H_2}O\, \rightleftharpoons {H_3}{O^ + } + HCO_3^ - $
for which the equilibrium constant is $3.8 \times 10^{-7}$ and $pH = 6.0$. The ratio of $[HCO_3^- ]$ to $[CO_2]$ would be :-
Which of the following statements is $/$ are Correct for $'Y'$