MCQ
For a $d$ electron, the orbital angular momentum is
- ✓$\sqrt {6\hbar } $
- B$\sqrt {2\hbar } $
- C$\hbar $
- D$2\hbar $
For $d -$ orbital, $1=2$
Thus, the orbital angular momentum is $=\sqrt{6} \frac{ h }{2 \pi}$
$\sqrt {6\hbar } $
Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.
$\begin{array}{*{20}{c}}
{C{H_2} = CHC{H_2}CHC{H_3} + KOH\xrightarrow[{heat}]{{{\text{alcohol}}}}} \\
{|\,\,\,\,\,\,\,\,\,\,\,\,\,\,} \\
{Br\,\,\,\,\,\,\,\,\,\,\,\,\,\,}
\end{array}$
$PCl_{5(g)} \rightleftharpoons PCl_{3(g)} + Cl_{2(g)}$
which of the following conditions are correct ?