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Wave Optics — Physics STD 12 Science — Question

Maharashtra BoardEnglish MediumSTD 12 SciencePhysicsWave Optics3 Marks
Question
For a given medium, the polarizing angle is $60^{\circ}$. What is the critical angle for this medium ?
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Answer

Data : $\theta_{ B }=60^{\circ}$
$n-\tan \theta_{ b }-\tan 60^{\circ}=\sqrt{3}$
$\sin \theta_c-\frac{1}{n}=\frac{1}{\sqrt{3}}=0.5773$
$\therefore \theta_e=\sin ^{-1}(0.5773)-35^{\circ} 16^{\prime}$
This is the critical angle for the medium.

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