MCQ
For a liquid normal boiling point is $-173\,^oC$ then at $2\ atm$ pressure it's boiling point should be nearly ......... $^oC.$ $(\Delta H_{vap} = 200\ cal/mole,\ R = 2 \ cal/mol-K,\,\,\ln \,2 = 0.7)$
- A$-73$
- B$333$
- ✓$60$
- D$103$
✓
Answer
Correct option: C.
$60$
c
$\ln \frac{\mathrm{P}_{2}}{\mathrm{P}_{1}}=\frac{\Delta \mathrm{H}}{\mathrm{R}}\left(\frac{1}{\mathrm{T}_{1}}-\frac{1}{\mathrm{T}_{2}}\right)$
$\ln \frac{\mathrm{P}_{2}}{\mathrm{P}_{1}}=\frac{\Delta \mathrm{H}}{\mathrm{R}}\left(\frac{1}{\mathrm{T}_{1}}-\frac{1}{\mathrm{T}_{2}}\right)$
$\ln \frac{2}{1}=\frac{200}{2}\left[\frac{1}{100}-\frac{1}{\mathrm{T}_{2}}\right]$
$\mathrm{T}_{2}=\frac{100}{0.3}=333.33\,\mathrm{K}=60.33\,^{o} \mathrm{C}$
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