MCQ
For a non-zero rational number $p, p^{13} \div p^8$ is equal to:
- ✓$p^5$
- B$p^{21}$
- C$p^{-5}$
- D$p^{-19}$
✓
Answer
Correct option: A.
$p^5$
A. $p^{5}$
Solution:
Using law of exponents, $a^m \div a^n = (a)^{m-n}$ [$\because$ a is non-zero integer]
Similarly
$p^{13} \div p^8 = (p)^{13-8}$
=$p^{5}$
Solution:
Using law of exponents, $a^m \div a^n = (a)^{m-n}$ [$\because$ a is non-zero integer]
Similarly
$p^{13} \div p^8 = (p)^{13-8}$
=$p^{5}$
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