MCQ
For a non-zero rational number $x,$ $x^8 ÷ x^2$ is equal to:
- A$x^4$
- ✓$x^6$
- C$x^{10}$
- D$x^{16}$
We know that, if $‘a’$ is a rational number, $m$ and $n$ are natural numbers such that $m> n$, then.
$a^m ÷ a^n$
$= a^{m-n}$
So, $\text{x}\div\text{x}^{2}=\frac{\text{x}^{8}}{\text{x}^{2}}$
$=\text{x}^{8-2}=\text{x}^{6}$
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