Question
For a $p -$ block element, its $3d, 3s, 3p$ and $4s$ orbitals are completely filled and the differentiating electron goes to the $4p$ orbital. The element should have its atomic number in the range

Answer

c
(c) $31-36 $ $\Rightarrow$ $Ga$ to $Kr$.

Need a full question paper?

Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.

Start Generating Free

Similar questions

How many primary, secondary, tertiary and quaternary carbons are present in the following hydrocarbon

$C{H_3} - CH(C{H_3}) - C{(C{H_3})_2} - C{H_2} - CH(C{H_3}) - C{H_2} - C{H_3}$

 

Primary

Secondary

Tertiary

Quaternary

 $(a)$

         $6$

         $2$

       $2$

         $1$

 $(b)$

         $2$

         $6$

       $3$

         $0$

 $(c)$

        $2$

        $4$

       $3$

         $2$

 $(d)$

        $2$

        $2$

       $4$

         $3$

The CORRECT order of first ionisation enthalpy is:
Which of the following is not used as a Lewis acid
Arrange the following in order of decreasing number of unpaired electrons :
i. $\left[ Fe \left( H _2 O \right)_6\right]^{2+}$
ii. $\left[ Fe ( CN )_6\right]^{3-}$
iii. $\left[ Fe ( CN )_6\right]^{2-}$
iv. $\left[ Fe \left( H _2 O \right)_6\right]^{3+}$
When acetylene is passed into dilute sulphuric acid containing $H{g^{2 + }}$ ions, the product formed is
The energy of an electron in excited hydrogen atom is $-3.4 \,eV.$ Then, according to Bohr's theory the angular momentum of this electron in $Jsec$ is
Given below are two statements: one is labelled as Assertion $(A)$ and the other is labelled as Reason $(R).$

Assertion $(A):$ Synthesis of ethyl phenyl ether may be achieved by Williamson synthesis.

Reason $(R):$ Reaction of bromobenzene with sodium ethoxide yields ethyl phenyl ether.

In the light of the above statements, choose the most appropriate answer from the options given below:

A hydrocarbon contains $86\%$ carbon, $488\,ml$ of the hydrocarbon weight $1.68\, g$ at $STP$. Then the hydrocarbon is an
Match List $- I$ with List$-II.$

List $- I$ List $- II$
$(a)$ $\left[\mathrm{Fe}(\mathrm{CN})_{6}\right]^{3-}$ $(i)$ $5.92 \,\mathrm{BM}$
$(b)$ $\left[\mathrm{Fe}\left(\mathrm{H}_{2} \mathrm{O}\right)_{6}\right]^{3+}$ $(ii)$ $0 \,\mathrm{BM}$
$(c)$ $\left[\mathrm{Fe}(\mathrm{CN})_{6}\right]^{4-}$ $(iii)$ $4.90\, \mathrm{BM}$
$(d)$ $\left[\mathrm{Fe}\left(\mathrm{H}_{2} \mathrm{O}\right)_{6}\right]^{2+}$ $(iv)$ $1.73\, \mathrm{BM}$

Choose the correct answer from the options given below.