MCQ
For a particle moving under the action of a variable force, kinetic energy-position graph is given, then
  • A
    At $A$ particle is decelerating
  • B
    At $B$ particle is accelerating
  • C
    At $C$ particle has maximum velocity
  • At $D$ particle has maximum acceleration

Answer

Correct option: D.
At $D$ particle has maximum acceleration
d
(d)

$F . d x=d K$

$\frac{d K}{d x}=F$

$\Rightarrow$ Slope of $K-x$ curve gives force

So slope is max at $D$, hence acceleration is maximum at $D$

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